W3School TIY Editor

#include <stdio.h> int main() { int numbers[] = {3, -1, 7, 0, 9}; int length = sizeof(numbers) / sizeof(numbers[0]); int i; for (i = 0; i < length; i++) { if (numbers[i] < 0) { continue; // 跳过负数 } if (numbers[i] == 0) { break; // 找到零时停止循环 } printf("%d\n", numbers[i]); } return 0; }